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  <front>
    <journal-meta><journal-id journal-id-type="publisher">MS</journal-id><journal-title-group>
    <journal-title>Mechanical Sciences</journal-title>
    <abbrev-journal-title abbrev-type="publisher">MS</abbrev-journal-title><abbrev-journal-title abbrev-type="nlm-ta">Mech. Sci.</abbrev-journal-title>
  </journal-title-group><issn pub-type="epub">2191-916X</issn><publisher>
    <publisher-name>Copernicus Publications</publisher-name>
    <publisher-loc>Göttingen, Germany</publisher-loc>
  </publisher></journal-meta>
    <article-meta>
      <article-id pub-id-type="doi">10.5194/ms-14-1-2023</article-id><title-group><article-title>Research on obstacle performance and tipping stability of a novel wheel–leg deformation mechanism</article-title><alt-title>Obstacle performance and stability of a wheel–leg mechanism​​​​​​​​​​​​​​​​​​​​​</alt-title>
      </title-group><?xmltex \runningtitle{Obstacle performance and stability of a wheel--leg mechanism​​​​​​​​​​​​​​​​​​​​​}?><?xmltex \runningauthor{M. Zhang and Y. Su}?>
      <contrib-group>
        <contrib contrib-type="author" corresp="yes" rid="aff1 aff2">
          <name><surname>Zhang</surname><given-names>Minghui</given-names></name>
          <email>m.h.zhang@sdust.edu.cn</email>
        </contrib>
        <contrib contrib-type="author" corresp="no" rid="aff1">
          <name><surname>Su</surname><given-names>Yiming</given-names></name>
          
        </contrib>
        <aff id="aff1"><label>1</label><institution>Department of Mechanical and Electronic Engineering, Shandong University of Science and Technology, Qingdao 266590, China​​​​​​​</institution>
        </aff>
        <aff id="aff2"><label>2</label><institution>Anhui Province Key Laboratory of Special Heavy Load Robot, Maanshan 243032, China</institution>
        </aff>
      </contrib-group>
      <author-notes><corresp id="corr1">Minghui Zhang (m.h.zhang@sdust.edu.cn)</corresp></author-notes><pub-date><day>5</day><month>January</month><year>2023</year></pub-date>
      
      <volume>14</volume>
      <issue>1</issue>
      <fpage>1</fpage><lpage>13</lpage>
      <history>
        <date date-type="received"><day>18</day><month>October</month><year>2022</year></date>
           <date date-type="rev-recd"><day>3</day><month>December</month><year>2022</year></date>
           <date date-type="accepted"><day>9</day><month>December</month><year>2022</year></date>
      </history>
      <permissions>
        <copyright-statement>Copyright: © 2023 Minghui Zhang</copyright-statement>
        <copyright-year>2023</copyright-year>
      <license license-type="open-access"><license-p>This work is licensed under the Creative Commons Attribution 4.0 International License. To view a copy of this licence, visit <ext-link ext-link-type="uri" xlink:href="https://creativecommons.org/licenses/by/4.0/">https://creativecommons.org/licenses/by/4.0/</ext-link></license-p></license></permissions><self-uri xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023.html">This article is available from https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023.html</self-uri><self-uri xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023.pdf">The full text article is available as a PDF file from https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023.pdf</self-uri>
      <abstract><title>Abstract</title>

      <p id="d1e93">A new type of wheel–leg deformation mechanism, based on an
electromagnetic clutch and gear rack transmission mechanism, is designed.
This mechanism has a compact structure and simple operation, which can roll on wheels and surmount obstacles with a support leg. Firstly, the walking model is established to study the kinematics characteristics of the mechanism. The
alternation of the support legs does not affect smooth obstacle crossing,
but will cause the step change of the angular velocity of the centroid of
the main body. Secondly, the obstacle-surmounting performance of roll-over
mode and obstacle-crossing mode using support legs is analyzed. For roll-over mode, the maximum climbing height is 87.36 mm. For obstacle-crossing
mode using support legs, the maximum climbing height is the maximum
extension length of the support leg. According to the climbing height, the
switching criteria of different climbing modes are obtained. In addition,
the rolling angle of the main body has a greater impact on the support force and driving torque, while the contact angle between the legs and the ground has a small impact. Finally, the tipping stability and anti-interference ability of the wheel–leg deformation mechanism is evaluated using the stability cone method.</p>
  </abstract>
    </article-meta>
  </front>
<body>
      

<sec id="Ch1.S1" sec-type="intro">
  <label>1</label><title>Introduction</title>
      <p id="d1e105">Exploiting the structural deformation principle, the wheel–leg deformation
mechanism integrates the wheel mechanism and the leg mechanism. With the
help of deformation or switching between the wheels and the legs, the
wheel–leg mobile mechanism possesses two motion modes: wheel rolling and leg
obstacle walking, which not only retains the excellent obstacle-crossing
performance of the leg mechanism, but also has the rapid movement ability of
wheel rolling. Thus, the wheel–leg mechanism has good adaptability to
complex road environment.</p>
      <p id="d1e108">In the early stage, the wheel–leg variant mechanism mostly adopted the
structure of rolling wheel deformation: the semicircular wheel was used as
the actuator of wheel–leg deformation switching. Sun et al. (2022) proposed
a wheel–leg mechanism composed of involute curve and circular arc, which can
walk, run, and cross obstacles in rough terrain. Yuan et al. (2022) designed a semicircle arc wheel–leg deformation mechanism based on the
transformation of multi-link structure, which can realize the sliding of
round pipe and the leg-type obstacle-crossing movement according to
different environments. In addition, Vina and Barrientos (2021) and Yamamoto and Aoki (2020) have studied the C-leg hybrid mobile robot: on flat ground, it can roll smoothly; and when climbing the boss, the end of the semicircular wheel
is used as the support leg and the front wheel and the rear wheel of the
vehicle body crosses the obstacle alternately in a butterfly gait. Tan et al. (2019) designed a wheel–leg reconfigurable robot, which uses the
semicircular wheel as the leg of the robot, and in the meantime, two
semicircular wheels on the same side rotate to form a wheel structure. Wang and Lin (2021) and Lin et al. (2018) proposed a wheel–leg
deformable robot named turboquad. The wheel–leg structure adopts the
transformation mode of vertical I-shape separation of two semicircular
wheel–legs to ensure continuous movement. Chen et al. (2021) used the
double-link mechanism as a semicircular rim. When the motor drives, two
V-shaped links to extend, and the rolling wheels are switched from the wheel
type state to the V-shaped leg type state. Ning et al. (2017) designed a
wheel–leg rescue robot with double semi-circular arc hub structure. If the
semicircular wheel hub is closed, the robot is in wheel motion mode. If the
semicircular wheel is folded along the central axis, the robot is in leg
motion mode.</p>
      <p id="d1e111">When crossing vertical obstacles or irregular obstacles such as steps and
bosses, the semi-circular wheel structure is not stable enough. Researchers
have been improving the deformation mechanism of the wheel–legs. Ding and Zhang (2022) designed a variable diameter wheel–leg obstacle-surmounting robot.
Three groups of arc legs are driven to extend outward by connecting rod
transmission to realize diameter change. When the arc legs retract the hub,
they switch to wheel type state. Zhang et al. (2021) proposed a wheel-leg
switching mode with scissors structure. The wheel–leg mobile robot designed
by Xu et al. (2021) has three groups of arc-shaped legs that can protrude
from the inside of the rolling wheel with the help of the four-bar
structure, the robot is able to switch to the leg-type obstacle-crossing
movement mode. The wheel–leg deformation robot developed by Ryu et al. (2020) uses the wheel rotation to generate centrifugal force, so that the
mechanism is transformed from the wheel shape to the arc wheel–leg shape.
Teng (2020) and Kim et al. (2020, 2019)
divide the rolling wheels into three groups of arc wheels as the leg
structure of the robot. By controlling the expansion and contraction of the
link structure, the robot can switch between the wheel mode and leg mode.
Cong et al. (2021) used a plane spiral pair to transmit the rotational
power to the arc-shaped wheel–legs, the rolling wheel was switched from the
round wheel state to four groups of arc-shaped wheel–legs. The wheel–leg
transformation robots designed in the references Lee et al. (2022), Lv (2020), Zeng et al. (2019), and Mertyüz et al. (2020) adopt six wheel–legs arranged
in the circumferential direction, and each wheel–leg can be independently
transformed during obstacle crossing. In addition, Tholapu et al. (2021)
proposed a conceptual spherical mobile robot, which is composed of two
hemispheres, and each hemisphere is divided into four legs. In the status of
stretching, the robot can walk like a quadruped robot, and while closing into a
sphere, the robot can roll. Zhai et al. (2021) designed a wheel–leg
variable robot based on the principle of iris structural deformation. The
robot can roll forward on the flat ground and can switch to the petal leg
obstacle mode when encountering obstacles.</p>
      <p id="d1e114">In addition to the wheel–leg deformation robot that directly transforms the
hub into a leg, there is another kind of wheel-legged variant mobile robot
that includes the leg structure in the rolling wheel or the fuselage. When
the robot encounters obstacles, the leg structure is driven by the
transmission mechanism to extend from the rolling wheel or the fuselage.
When the ground is flat, the leg structure is retracted into the rolling
wheel or the fuselage internal structure. This kind of robot can switch the
movement mode autonomously according to the environment and has stronger
adaptability and stability. The 2-DOF motion robot designed by Zhang (2021) and Zhang and Sun (2021) is composed of rolling wheels and telescopic
adjustable links. Baishya et al. (2021) proposed an anti-skid mechanism
for climbing steps, consisting of three motion chains and four-bar mechanism,
which controls the mutual switching between the rolling wheel and the
structural leg by using the current thermal effect and the elastic potential
energy of the spring. The wheel–leg mobile robot designed by Sanchez and Bhounsule (2021) is composed of several adjustable telescopic legs. When crossing
the obstacle, the robot realizes rotation and climbing by means of the
contact point between the end of the leg and the obstacle. Xie et al. (2021) proposed a new type of two-way inchworm pipeline robot, which
drives the leg structure to expand and contract through the rotation of the
cam to realize the two-way crawling of the robot in the pipeline. In the
spherical quadruped robot studied by Aoki et al. (2020), the legs
alternately extend from the inside of the spherical shell and kick to the
ground when climbing steps, pushing the fuselage to climb over the steps.
Song et al. (2022) proposed a wheel–leg deformation structure, which
drives the sliding leg to extend from the guide rail through the crank
linkage mechanism to complete the switch from wheel type to spoke leg type
structure.</p>
      <p id="d1e118">The scholars have done a lot of work on the wheel–leg variant mobile robot,
which mainly focuses on the design and kinematic analysis of the new
wheel–leg deformation mechanism. However, there are still problems such as
the wheel–leg deformation mechanism being too complex and the wheel–leg
switching criteria lacking theoretical basis. In addition, there is little
analysis on the motion stability and anti-interference ability of the
wheel–leg deformation mechanism. Therefore, the following work has been done
in this paper: (1) a new type of wheel–leg deformation mechanism with
compact structure and simple operation has been designed. The mechanism can
roll on wheels and surmount obstacles with support leg mode by means of
electromagnetic clutch and gear rack transmission mechanism. (2) The walking
model is established to study the kinematic characteristics and obstacle-surmounting performance of the mechanism. The wheel-legged switching
criterion of mechanism is formulated. (3) The stability cone method is used
to evaluate the rollover stability and anti-interference ability in order to
ensure the normal operation of the mechanism.</p>
      <p id="d1e121">The paper is organized as follows: Sect. 2 first outlines the structure of
the wheel–leg deformation mechanism and the working principle of wheel–leg
switch. Section 3 describes the obstacle-surmounting performance and tipping
stability of the mechanism. Finally, the findings of the present study are
concluded.</p>
</sec>
<sec id="Ch1.S2">
  <label>2</label><title>Problem description and methodological design</title>
      <p id="d1e132">A new type of wheel–leg deformation mechanism is proposed, which has strong
adaptability to complex terrain and can cross over gullies, climb up and
down steps, and roll on flat roads. According to the requirements of the
application environment of the mechanism, the mass of the wheel–leg
deformation mechanism should not be greater than 10 kg, the rolling speed of
the flat ground should not be less than 1.5 m s<inline-formula><mml:math id="M1" display="inline"><mml:msup><mml:mi/><mml:mrow><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msup></mml:math></inline-formula>, the climbing angle should
not be less than 10<inline-formula><mml:math id="M2" display="inline"><mml:msup><mml:mi/><mml:mo>∘</mml:mo></mml:msup></mml:math></inline-formula>, the climbing speed should not be less than
0.5 m s<inline-formula><mml:math id="M3" display="inline"><mml:msup><mml:mi/><mml:mrow><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msup></mml:math></inline-formula>, the climbing step speed in the leg state should not less than 10 steps min<inline-formula><mml:math id="M4" display="inline"><mml:msup><mml:mi/><mml:mrow><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msup></mml:math></inline-formula>, the climbing step height should not be less than 200 mm, and the width of the crossing gully shall not be less than 200 mm.</p>
<sec id="Ch1.S2.SS1">
  <label>2.1</label><title>Structural design of wheel–leg deformation mechanism</title>
      <p id="d1e187">The leg telescopic structure is composed of two sets of fixed frames and 24
contact feet, as shown in Fig. 1a. Each set of fixed frames includes one
fixed disk and 24 gears, racks, sliding support plates, and electromagnetic
clutches, which are evenly distributed along the circumferential direction,
as shown in Fig. 1b. Connect the same direction rack on the two sets of
fixed frames with the contact foot through bolts to form a telescopic leg.
The electromagnetic clutch cooperates with the gear and rack to realize the
independent movement of each telescopic leg.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F1" specific-use="star"><?xmltex \currentcnt{1}?><?xmltex \def\figurename{Figure}?><label>Figure 1</label><caption><p id="d1e192">The leg telescopic structure.</p></caption>
          <?xmltex \igopts{width=355.659449pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f01.png"/>

        </fig>

<?xmltex \floatpos{t}?><table-wrap id="Ch1.T1" specific-use="star"><?xmltex \currentcnt{1}?><label>Table 1</label><caption><p id="d1e204">Wheel and leg deformation mechanism parameters.</p></caption><oasis:table frame="topbot"><oasis:tgroup cols="4">
     <oasis:colspec colnum="1" colname="col1" align="left"/>
     <oasis:colspec colnum="2" colname="col2" align="left"/>
     <oasis:colspec colnum="3" colname="col3" align="left"/>
     <oasis:colspec colnum="4" colname="col4" align="left"/>
     <oasis:thead>
       <oasis:row rowsep="1">
         <oasis:entry colname="col1">Parameter</oasis:entry>
         <oasis:entry colname="col2">Value</oasis:entry>
         <oasis:entry colname="col3">Parameter</oasis:entry>
         <oasis:entry colname="col4">Value</oasis:entry>
       </oasis:row>
     </oasis:thead>
     <oasis:tbody>
       <oasis:row>
         <oasis:entry colname="col1">Total weight <inline-formula><mml:math id="M5" display="inline"><mml:mi>M</mml:mi></mml:math></inline-formula></oasis:entry>
         <oasis:entry colname="col2">8 kg</oasis:entry>
         <oasis:entry colname="col3">Width of rolling wheel</oasis:entry>
         <oasis:entry colname="col4">50 mm</oasis:entry>
       </oasis:row>
       <oasis:row>
         <oasis:entry colname="col1">Radius of rolling wheel <inline-formula><mml:math id="M6" display="inline"><mml:mi>R</mml:mi></mml:math></inline-formula></oasis:entry>
         <oasis:entry colname="col2">200 mm</oasis:entry>
         <oasis:entry colname="col3">Track width of rolling wheel <inline-formula><mml:math id="M7" display="inline"><mml:mi>B</mml:mi></mml:math></inline-formula></oasis:entry>
         <oasis:entry colname="col4">100 mm</oasis:entry>
       </oasis:row>
       <oasis:row>
         <oasis:entry colname="col1">Single leg mass <inline-formula><mml:math id="M8" display="inline"><mml:mrow><mml:msub><mml:mi>M</mml:mi><mml:mi>T</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula></oasis:entry>
         <oasis:entry colname="col2">0.25 kg</oasis:entry>
         <oasis:entry colname="col3">Maximum telescopic length of single leg</oasis:entry>
         <oasis:entry colname="col4">120 mm</oasis:entry>
       </oasis:row>
       <oasis:row>
         <oasis:entry colname="col1">Scroll speed</oasis:entry>
         <oasis:entry colname="col2">1.8 m s<inline-formula><mml:math id="M9" display="inline"><mml:msup><mml:mi/><mml:mrow><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msup></mml:math></inline-formula></oasis:entry>
         <oasis:entry colname="col3">Extension time of one leg</oasis:entry>
         <oasis:entry colname="col4">1.5 s</oasis:entry>
       </oasis:row>
       <oasis:row>
         <oasis:entry colname="col1">Maximum climbing speed</oasis:entry>
         <oasis:entry colname="col2">1 m s<inline-formula><mml:math id="M10" display="inline"><mml:msup><mml:mi/><mml:mrow><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msup></mml:math></inline-formula></oasis:entry>
         <oasis:entry colname="col3">Effective time of single leg action</oasis:entry>
         <oasis:entry colname="col4">0.5 s</oasis:entry>
       </oasis:row>
       <oasis:row>
         <oasis:entry colname="col1">Maximum climbing step speed</oasis:entry>
         <oasis:entry colname="col2">10 step min<inline-formula><mml:math id="M11" display="inline"><mml:msup><mml:mi/><mml:mrow><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msup></mml:math></inline-formula></oasis:entry>
         <oasis:entry colname="col3"/>
         <oasis:entry colname="col4"/>
       </oasis:row>
     </oasis:tbody>
   </oasis:tgroup></oasis:table></table-wrap>

      <p id="d1e393">The overall structure of the wheel–leg deformation mechanism is shown in
Fig. 2. The whole deformation mechanism includes the following: (1) control unit; (2) inertial measurement unit; (3) vision sensor; (4) laser radar; (5) lithium battery; (6) sealing cover; (7) drive motor; (8) leg contact foot; (9) rolling wheel; (10) slide rail support plate; (11) rack; and (12) enclosure. Relevant
design parameters of wheel–leg deformation mechanism are shown in Table 1.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F2"><?xmltex \currentcnt{2}?><?xmltex \def\figurename{Figure}?><label>Figure 2</label><caption><p id="d1e398">Overall structure of wheel–leg deformation mechanism.</p></caption>
          <?xmltex \igopts{width=241.848425pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f02.png"/>

        </fig>

</sec>
<sec id="Ch1.S2.SS2">
  <label>2.2</label><title>Mechanism of wheel-legged movement mode switching</title>
      <p id="d1e415">According to the application scenarios and design requirements of the
wheel–leg deformation mechanism, the mechanism rolls forward on the flat
road, as shown in Fig. 3a. When the rolling wheel cannot cross
complex road conditions such as steps and gullies, it will switch to the leg
type obstacle-crossing mode, as shown in Fig. 3b.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F3" specific-use="star"><?xmltex \currentcnt{3}?><?xmltex \def\figurename{Figure}?><label>Figure 3</label><caption><p id="d1e420">Motion mode of wheel leg deformation mechanism.</p></caption>
          <?xmltex \igopts{width=327.206693pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f03.png"/>

        </fig>

      <p id="d1e429">The following will introduce the working principles of the two motion modes
in combination with the internal transmission system diagram of the
mechanism, as shown in Fig. 4. Where I is the motor input shaft; A, B, C,
and D are electromagnetic clutches; 1 is driving center wheel in leg mode; 2
is driving center wheel in rolling mode; 3, 4, 8, and 9 are gears; 5 is a
rolling wheel; and 6 and 7 are timing pulleys.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F4"><?xmltex \currentcnt{4}?><?xmltex \def\figurename{Figure}?><label>Figure 4</label><caption><p id="d1e435">The internal drive system of the mechanism.</p></caption>
          <?xmltex \igopts{width=241.848425pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f04.png"/>

        </fig>

<?xmltex \hack{\newpage}?>
<sec id="Ch1.S2.SS2.SSS1">
  <label>2.2.1</label><title>Wheel scroll mode</title>
      <p id="d1e453">The motor transmits the driving torque to the input shaft I, and the
electromagnetic clutch A is energized. The power drives the rolling wheel 5
to rotate through the sun gear 2 and the planetary gear 4. Since the
electromagnetic clutch B is in the power-off state, the driving torque
cannot be transmitted to the synchronous pulley at the lower side of the
electromagnetic clutch B, and the leg structure contracts inside the
deformation mechanism, so that the mechanism can roll forward on the flat
ground.</p>
</sec>
<sec id="Ch1.S2.SS2.SSS2">
  <label>2.2.2</label><title>Leg obstacle mode</title>
      <p id="d1e464">When the wheel–leg deformation mechanism encounters an obstacle that the
rolling wheel cannot climb over, the electromagnetic clutch A is powered
off, and the electromagnetic clutch B is switched from the power-off state
to the power-on state. After the motor is regulated, the driving torque is
transmitted to the lower synchronous pulley 6 of the electromagnetic clutch B through the gear 3 of the planetary gear train. The electromagnetic clutch C is energized, and the power is transmitted to the rack meshing with the
gear 8 via the timing pulley 7, and the contact foot is extended. When the
travel switch installed at the end of the rack is touched, the
electromagnetic clutch B is cut off, the electromagnetic clutch D on the
opposite side is energized, and the leg structure is retracted inside the
mechanism.</p>
</sec>
</sec>
<sec id="Ch1.S2.SS3">
  <label>2.3</label><title>Gait planning of legged obstacle walking</title>
      <p id="d1e476">When the wheel–leg deformation mechanism encounters steps and gullies, the
contact feet extend alternately to push the body upward. According to the
nomenclature principle of leg mechanism, the contact legs extending
alternately are defined as support legs and swing legs. The contact foot
that is far away from the step, in contact with the ground, and plays a
supporting role is called the support leg, and the contact foot that is near
the step, in the extended state, and is not in contact with the ground is
called the swing leg. Take climbing steps as an example, the obstacle-crossing process is divided into four stages: (1) the stage of the support leg 1 extension. When the body of the deformation mechanism touches the step,
the contact foot (in the opposite direction of movement) closest to vertical
line through centroid extends and the contact foot (support leg 1) collides
with the ground to trigger the extension of its adjacent inner contact foot
(swing leg 1), as shown in Fig. 5a. (2) The support leg 1 supports and
pushes the fuselage upward. Support leg 1 extends to the maximum elongation,
and then swing leg 1 contacts the ground, as shown in Fig. 5b. (3) The
swing leg 1 is converted into a support leg 2. After the swing leg 1
contacts the ground, the support leg 1 retracts and the swing leg 2 starts
to extend. The swing leg 1 supports and pushes the fuselage upward as the
support leg 2, as shown in Fig. 5c. (4) Repeat the above process until
the center of mass of the body crosses the boundary line of the obstacle,
the contact foot retracts and climbs up the obstacle with the body, as shown
in Fig. 5d.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F5" specific-use="star"><?xmltex \currentcnt{5}?><?xmltex \def\figurename{Figure}?><label>Figure 5</label><caption><p id="d1e481">Gait planning of legged obstacle walking.</p></caption>
          <?xmltex \igopts{width=312.980315pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f05.png"/>

        </fig>

      <p id="d1e490">When the wheel–leg deformation mechanism goes down the step, the movement
process of its leg structure is opposite to that of the upper step. When the
mechanism goes over the gully, it can be regarded as the movement
combination of the upper and lower steps.</p>
</sec>
</sec>
<sec id="Ch1.S3">
  <label>3</label><title>Results and discussions</title>
      <p id="d1e502">When the wheel–leg deformation mechanism moves in the complex road
environment, it needs to use the leg structure to extend alternately to push
the fuselage over obstacles. The obstacle-surmounting performance and stable
working conditions of the mechanism are analyzed.</p><?xmltex \hack{\newpage}?>
<sec id="Ch1.S3.SS1">
  <label>3.1</label><title>Kinematic analysis of legged obstacle walking</title>
      <p id="d1e513">The schematic diagram of the <inline-formula><mml:math id="M12" display="inline"><mml:mi>k</mml:mi></mml:math></inline-formula>th and <inline-formula><mml:math id="M13" display="inline"><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:math></inline-formula>th movements of the support leg
and the swing leg when the wheel–leg deformation mechanism crosses the
obstacle is shown in Fig. 6. When the support leg just touches the ground,
the extended length is <inline-formula><mml:math id="M14" display="inline"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi>l</mml:mi><mml:mrow><mml:mi>s</mml:mi><mml:mi>k</mml:mi></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula>, and the included angle between
the support leg and the ground is <inline-formula><mml:math id="M15" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">α</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>. The centroid of the
supporting leg extending out of the main body is <inline-formula><mml:math id="M16" display="inline"><mml:mrow><mml:msub><mml:mi>C</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>. The centroid of the
body is <inline-formula><mml:math id="M17" display="inline"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>. The contact point between the mechanism body and the step is
point <inline-formula><mml:math id="M18" display="inline"><mml:mi>B</mml:mi></mml:math></inline-formula>. The distance between the centroid of the main body and the contact
point is <inline-formula><mml:math id="M19" display="inline"><mml:mrow><mml:mi>B</mml:mi><mml:msub><mml:mi>O</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mi>R</mml:mi></mml:mrow></mml:math></inline-formula>. The angle between the connecting line <inline-formula><mml:math id="M20" display="inline"><mml:mrow><mml:mi>B</mml:mi><mml:msub><mml:mi>O</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> and the ground is <inline-formula><mml:math id="M21" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">φ</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>. When the extension of the support leg
reaches the maximum, the length is
<inline-formula><mml:math id="M22" display="inline"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">0</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula>, and the included angle between the support
leg and the ground is <inline-formula><mml:math id="M23" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">α</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula>. At this time, the swinging leg
contacts the ground, and the extension length is
<inline-formula><mml:math id="M24" display="inline"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi>l</mml:mi><mml:mrow><mml:mi>s</mml:mi><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula>. The centroid of the supporting
leg extending out of the main body is <inline-formula><mml:math id="M25" display="inline"><mml:mrow><mml:msub><mml:mi>C</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>.</mml:mo></mml:mrow></mml:math></inline-formula> The centroid of the body
is <inline-formula><mml:math id="M26" display="inline"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula>. The angle between the connecting line
<inline-formula><mml:math id="M27" display="inline"><mml:mrow><mml:mi>B</mml:mi><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula> and the ground is <inline-formula><mml:math id="M28" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">φ</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula>. The coordinate system is established, the motion direction is the <inline-formula><mml:math id="M29" display="inline"><mml:mi>x</mml:mi></mml:math></inline-formula> axis, the
vertical ground direction is the <inline-formula><mml:math id="M30" display="inline"><mml:mi>z</mml:mi></mml:math></inline-formula> axis, the coordinate origin is the contact point between the support leg 1 and the ground.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F6"><?xmltex \currentcnt{6}?><?xmltex \def\figurename{Figure}?><label>Figure 6</label><caption><p id="d1e813">The legged overrun walking model.</p></caption>
          <?xmltex \igopts{width=227.622047pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f06.png"/>

        </fig>

      <p id="d1e822">Assuming that the height of the step is <inline-formula><mml:math id="M31" display="inline"><mml:mi>H</mml:mi></mml:math></inline-formula>, the mass of the body is <inline-formula><mml:math id="M32" display="inline"><mml:mi>M</mml:mi></mml:math></inline-formula>, and the mass of the single leg is <inline-formula><mml:math id="M33" display="inline"><mml:mrow><mml:msub><mml:mi>M</mml:mi><mml:mi>T</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>, the speed of leg extension is <inline-formula><mml:math id="M34" display="inline"><mml:mi>V</mml:mi></mml:math></inline-formula>. Let
<inline-formula><mml:math id="M35" display="inline"><mml:mrow><mml:msub><mml:mi>C</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi>r</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mo>(</mml:mo><mml:msub><mml:mi>l</mml:mi><mml:mrow><mml:mi>s</mml:mi><mml:mi>k</mml:mi></mml:mrow></mml:msub><mml:mo>-</mml:mo><mml:mi>R</mml:mi><mml:mo>)</mml:mo><mml:mo>/</mml:mo><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:math></inline-formula> and <inline-formula><mml:math id="M36" display="inline"><mml:mrow><mml:msub><mml:mi>C</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi>r</mml:mi><mml:mrow><mml:mn mathvariant="normal">0</mml:mn><mml:mi>k</mml:mi></mml:mrow></mml:msub><mml:mo>=</mml:mo><mml:mo>(</mml:mo><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">0</mml:mn></mml:msub><mml:mo>-</mml:mo><mml:mi>R</mml:mi><mml:mo>)</mml:mo><mml:mo>/</mml:mo><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:math></inline-formula>. When the wheel–leg deformation
mechanism crosses the obstacle, Eqs. (1)–(4) shall be satisfied.

                <disp-formula specific-use="gather" content-type="numbered"><mml:math id="M37" display="block"><mml:mtable displaystyle="true"><mml:mlabeledtr id="Ch1.E1"><mml:mtd><mml:mtext>1</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle displaystyle="true" class="stylechange"/><mml:mtable rowspacing="0.2ex" class="split" displaystyle="true" columnalign="right left"><mml:mtr><mml:mtd><mml:mrow><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">0</mml:mn></mml:msub></mml:mrow></mml:mtd><mml:mtd><mml:mrow><mml:mo>=</mml:mo><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:msub><mml:mi>l</mml:mi><mml:mrow><mml:mi>s</mml:mi><mml:mi>k</mml:mi></mml:mrow></mml:msub><mml:mo>=</mml:mo><mml:mfenced close="∥" open="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mi>R</mml:mi><mml:mo>=</mml:mo><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mi>B</mml:mi></mml:mrow></mml:mfenced><mml:mi>R</mml:mi></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mo>=</mml:mo><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mi>B</mml:mi></mml:mrow></mml:mfenced><mml:msub><mml:mi>l</mml:mi><mml:mrow><mml:mi>s</mml:mi><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>=</mml:mo><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:mfenced></mml:mrow></mml:mtd></mml:mtr></mml:mtable></mml:mrow></mml:mtd></mml:mlabeledtr><mml:mlabeledtr id="Ch1.E2"><mml:mtd><mml:mtext>2</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle displaystyle="true" class="stylechange"/><mml:mtable rowspacing="0.2ex" class="split" displaystyle="true" columnalign="right left"><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mfenced close="∥" open="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mi>sin⁡</mml:mi><mml:mo>(</mml:mo><mml:mi mathvariant="italic">π</mml:mi><mml:mo>-</mml:mo><mml:msub><mml:mi mathvariant="italic">α</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>)</mml:mo><mml:mo>-</mml:mo><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mi>sin⁡</mml:mi><mml:mo>(</mml:mo><mml:mi mathvariant="italic">π</mml:mi><mml:mo>-</mml:mo><mml:msub><mml:mi mathvariant="italic">α</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mo>)</mml:mo></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mspace linebreak="nobreak" width="1em"/><mml:mo>=</mml:mo><mml:mfenced close="∥" open="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mi>B</mml:mi></mml:mrow></mml:mfenced><mml:mi>sin⁡</mml:mi><mml:msub><mml:mi mathvariant="italic">φ</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>-</mml:mo><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mi>B</mml:mi></mml:mrow></mml:mfenced><mml:mi>sin⁡</mml:mi><mml:msub><mml:mi mathvariant="italic">φ</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:mtd></mml:mtr></mml:mtable></mml:mrow></mml:mtd></mml:mlabeledtr><mml:mlabeledtr id="Ch1.E3"><mml:mtd><mml:mtext>3</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle displaystyle="true" class="stylechange"/><mml:mtable class="split" rowspacing="0.2ex" displaystyle="true" columnalign="right left"><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:msup><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:mfenced><mml:mn mathvariant="normal">2</mml:mn></mml:msup><mml:mo>+</mml:mo><mml:msup><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mn mathvariant="normal">2</mml:mn></mml:msup><mml:mo>-</mml:mo><mml:mn mathvariant="normal">2</mml:mn><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:mfenced></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mspace width="1em" linebreak="nobreak"/><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mi>cos⁡</mml:mi><mml:mi mathvariant="italic">θ</mml:mi><mml:mo>=</mml:mo><mml:mfenced close="∥" open="∥"><mml:mrow><mml:msub><mml:mi>A</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>A</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced></mml:mrow></mml:mtd></mml:mtr></mml:mtable></mml:mrow></mml:mtd></mml:mlabeledtr><mml:mlabeledtr id="Ch1.E4"><mml:mtd><mml:mtext>4</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle displaystyle="true" class="stylechange"/><mml:msup><mml:mfenced close="∥" open="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mi>B</mml:mi></mml:mrow></mml:mfenced><mml:mn mathvariant="normal">2</mml:mn></mml:msup><mml:mo>+</mml:mo><mml:msup><mml:mfenced open="∥" close="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mi>B</mml:mi></mml:mrow></mml:mfenced><mml:mn mathvariant="normal">2</mml:mn></mml:msup><mml:mo>-</mml:mo><mml:mn mathvariant="normal">2</mml:mn><mml:msup><mml:mi>R</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msup><mml:mi>cos⁡</mml:mi><mml:mi mathvariant="italic">θ</mml:mi><mml:mo>=</mml:mo><mml:msup><mml:mfenced close="∥" open="∥"><mml:mrow><mml:msub><mml:mi>O</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>O</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mn mathvariant="normal">2</mml:mn></mml:msup><mml:mo>.</mml:mo></mml:mrow></mml:mtd></mml:mlabeledtr></mml:mtable></mml:math></disp-formula>

            Based on the instantaneous inelastic collision hypothesis, the energy
equation and momentum moment equation are established when the support leg
touches the ground and the support leg extends to the maximum. The equations
are as follows:
            <disp-formula id="Ch1.E5" content-type="numbered"><label>5</label><mml:math id="M38" display="block"><mml:mtable class="split" rowspacing="0.2ex" displaystyle="true" columnalign="right left"><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mn mathvariant="normal">1</mml:mn><mml:mn mathvariant="normal">2</mml:mn></mml:mfrac></mml:mstyle><mml:mi>M</mml:mi><mml:msup><mml:mi>R</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msup><mml:msubsup><mml:mi mathvariant="italic">ω</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow><mml:mn mathvariant="normal">2</mml:mn></mml:msubsup><mml:mo>+</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mn mathvariant="normal">1</mml:mn><mml:mn mathvariant="normal">2</mml:mn></mml:mfrac></mml:mstyle><mml:mi>M</mml:mi><mml:msubsup><mml:mi>V</mml:mi><mml:mrow><mml:mi>c</mml:mi><mml:mi>k</mml:mi><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow><mml:mn mathvariant="normal">2</mml:mn></mml:msubsup><mml:mo>+</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mn mathvariant="normal">1</mml:mn><mml:mn mathvariant="normal">2</mml:mn></mml:mfrac></mml:mstyle><mml:msub><mml:mi>M</mml:mi><mml:mi>T</mml:mi></mml:msub><mml:msup><mml:mi>V</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msup><mml:mo>+</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mn mathvariant="normal">1</mml:mn><mml:mn mathvariant="normal">2</mml:mn></mml:mfrac></mml:mstyle><mml:msub><mml:mi>M</mml:mi><mml:mi>T</mml:mi></mml:msub><mml:msubsup><mml:mi>r</mml:mi><mml:mi>k</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msubsup><mml:msup><mml:mfenced open="[" close="]"><mml:mrow><mml:msubsup><mml:mover accent="true"><mml:mi mathvariant="italic">α</mml:mi><mml:mo mathvariant="normal">˙</mml:mo></mml:mover><mml:mi>k</mml:mi><mml:mo>+</mml:mo></mml:msubsup></mml:mrow></mml:mfenced><mml:mn mathvariant="normal">2</mml:mn></mml:msup></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mspace linebreak="nobreak" width="1em"/><mml:mspace width="1em" linebreak="nobreak"/><mml:mo>+</mml:mo><mml:mfenced open="(" close=")"><mml:mrow><mml:mi>M</mml:mi><mml:msub><mml:mi>l</mml:mi><mml:mrow><mml:mi>s</mml:mi><mml:mi>k</mml:mi></mml:mrow></mml:msub><mml:mo>+</mml:mo><mml:msub><mml:mi>M</mml:mi><mml:mi>T</mml:mi></mml:msub><mml:msub><mml:mi>r</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mi>g</mml:mi><mml:mi>cos⁡</mml:mi><mml:msub><mml:mi mathvariant="italic">α</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mspace linebreak="nobreak" width="1em"/><mml:mo>=</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mn mathvariant="normal">1</mml:mn><mml:mn mathvariant="normal">2</mml:mn></mml:mfrac></mml:mstyle><mml:mi>M</mml:mi><mml:msup><mml:mi>R</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msup><mml:msubsup><mml:mi mathvariant="italic">ω</mml:mi><mml:mi>k</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msubsup><mml:mo>+</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mn mathvariant="normal">1</mml:mn><mml:mn mathvariant="normal">2</mml:mn></mml:mfrac></mml:mstyle><mml:mi>M</mml:mi><mml:msubsup><mml:mi>V</mml:mi><mml:mrow><mml:mi>c</mml:mi><mml:mi>k</mml:mi></mml:mrow><mml:mn mathvariant="normal">2</mml:mn></mml:msubsup><mml:mo>+</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mn mathvariant="normal">1</mml:mn><mml:mn mathvariant="normal">2</mml:mn></mml:mfrac></mml:mstyle><mml:msub><mml:mi>M</mml:mi><mml:mi>T</mml:mi></mml:msub><mml:msubsup><mml:mi>r</mml:mi><mml:mrow><mml:mn mathvariant="normal">0</mml:mn><mml:mi>k</mml:mi></mml:mrow><mml:mn mathvariant="normal">2</mml:mn></mml:msubsup><mml:msup><mml:mfenced open="[" close="]"><mml:mrow><mml:msubsup><mml:mover accent="true"><mml:mi mathvariant="italic">α</mml:mi><mml:mo mathvariant="normal">˙</mml:mo></mml:mover><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow><mml:mo>-</mml:mo></mml:msubsup></mml:mrow></mml:mfenced><mml:mn mathvariant="normal">2</mml:mn></mml:msup></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mspace width="1em" linebreak="nobreak"/><mml:mspace width="1em" linebreak="nobreak"/><mml:mo>+</mml:mo><mml:mfenced close=")" open="("><mml:mrow><mml:mi>M</mml:mi><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">0</mml:mn></mml:msub><mml:mo>+</mml:mo><mml:msub><mml:mi>M</mml:mi><mml:mi>T</mml:mi></mml:msub><mml:msub><mml:mi>r</mml:mi><mml:mrow><mml:mn mathvariant="normal">0</mml:mn><mml:mi>k</mml:mi></mml:mrow></mml:msub></mml:mrow></mml:mfenced><mml:mi>g</mml:mi><mml:mi>cos⁡</mml:mi><mml:msub><mml:mi mathvariant="italic">α</mml:mi><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:mtd></mml:mtr></mml:mtable></mml:math></disp-formula>

            <disp-formula id="Ch1.E6" content-type="numbered"><label>6</label><mml:math id="M39" display="block"><mml:mrow><mml:msub><mml:mi>M</mml:mi><mml:mi>T</mml:mi></mml:msub><mml:msubsup><mml:mi>r</mml:mi><mml:mi>k</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msubsup><mml:msubsup><mml:mover accent="true"><mml:mi mathvariant="italic">α</mml:mi><mml:mo mathvariant="normal">˙</mml:mo></mml:mover><mml:mi>k</mml:mi><mml:mo>+</mml:mo></mml:msubsup><mml:mo>=</mml:mo><mml:msub><mml:mi>M</mml:mi><mml:mi>T</mml:mi></mml:msub><mml:msubsup><mml:mi>r</mml:mi><mml:mrow><mml:mn mathvariant="normal">0</mml:mn><mml:mi>k</mml:mi></mml:mrow><mml:mn mathvariant="normal">2</mml:mn></mml:msubsup><mml:msubsup><mml:mover accent="true"><mml:mi mathvariant="italic">α</mml:mi><mml:mo mathvariant="normal">˙</mml:mo></mml:mover><mml:mrow><mml:mi>k</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow><mml:mo>-</mml:mo></mml:msubsup><mml:mo>.</mml:mo></mml:mrow></mml:math></disp-formula>
          It should be pointed out that when establishing the energy equation and
momentum equation, only the main body and the supporting leg is considered,
and the influence of the swinging leg is ignored. Use “<inline-formula><mml:math id="M40" display="inline"><mml:mo>-</mml:mo></mml:math></inline-formula>” to indicate before the impact between the contact foot and the ground occurs, “<inline-formula><mml:math id="M41" display="inline"><mml:mo>+</mml:mo></mml:math></inline-formula>” to indicate that the impact is just completed, and “<inline-formula><mml:math id="M42" display="inline"><mml:mi>k</mml:mi></mml:math></inline-formula>” to indicate the number of steps.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F7" specific-use="star"><?xmltex \currentcnt{7}?><?xmltex \def\figurename{Figure}?><label>Figure 7</label><caption><p id="d1e1810">Kinematic parameters changing with the time.</p></caption>
          <?xmltex \igopts{width=384.112205pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f07.png"/>

        </fig>

      <p id="d1e1819">Assume that the step height is 100 mm and the leg extension speed is 50 mm s<inline-formula><mml:math id="M43" display="inline"><mml:msup><mml:mi/><mml:mrow><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msup></mml:math></inline-formula>.
Combined with the design parameters of the mechanism, the kinematic
characteristics of the wheel–leg deformation mechanism over typical
obstacles are studied using the above theory. At the same time, the dynamic
simulation software ADAMS is used to simulate the actual movement process of
the mechanical system to verify the correctness of the leg-type obstacle-climbing theory of the wheel–leg deformation mechanism and the rationality
of the mechanical structure design. The comparison between theoretical
calculation and simulation analysis results of motion parameters is shown in
Fig. 7. It is shown that when climbing a step with a height of 100 mm, the
mechanism shall be supported by three contact feet alternately. When the
first supporting leg works, it is called the first step. When the second
supporting leg works, it is called the second step. When the third
supporting leg works, it is called the third step. The following parts are
named in the same way.</p>
      <p id="d1e1834">The change of the displacement of the centroid of the main body during the
climbing process is shown in Fig. 7a. It is shown that the displacement of
the body's centroid is a continuous smooth curve, and the simulation curve
is in good agreement with the theoretical curve. The alternation of the
support legs do not affect the smooth climbing of the mechanism. The change
of the angular velocity of the centroid of the main body with time is shown
in Fig. 7b. It is shown that the alternation of the supporting legs will
cause the step change of the angular velocity of the centroid. Even if the
support leg is the same, the angular velocity changes with the extension
length of the support leg. Different from the uniform rolling on the flat
road, the climbing process of mechanism is a process of accelerating
rolling. The angular velocity of simulation curve with some fluctuation is
relatively consistent with the theoretical curve, which is caused by the
collision between the leg extension and the ground. The change of the angle
between the support leg and the ground with time is shown in Fig. 7c. It
is shown that different support legs have different initial contact angles
with the ground. The contact angle increases with the extension of the leg.
The change of the rolling angle of the main body with time is shown in Fig. 7d. It is shown that the rolling angle increases gradually during rolling.
The initial value of the roll angle is related to the step height. When the
step height is equal to the body radius, the initial value of the roll angle
is zero.</p>
</sec>
<sec id="Ch1.S3.SS2">
  <label>3.2</label><title>Analysis of obstacle-surmounting performance</title>
      <p id="d1e1845">When the wheel-legged deformation mechanism climbs an obstacle, different
climbing methods can be adopted according to the height of the obstacle. (1) Roll-over mode: when the radius of the rolling wheel is far greater than the
height of the step, the mechanism can climb over the step by rolling. (2) Obstacle crossing mode using support legs: when the step height is greater
than the height that the rolling wheel can climb, but less than the extended
length of the support leg, the leg structure is used for climbing. (3) Climbing mode with mixed wheels and legs: when the step height is greater
than the extended length of the support leg, the leg structure can be used
to raise the body height first, and then the rolling wheel can be used to
climb over the step.</p>
      <p id="d1e1848">Note that the obstacle-surmounting performance of the wheel–leg hybrid mode
can be obtained from the previous two modes. Therefore, only roll-over mode
and obstacle-crossing mode using support legs are analyzed.</p>
      <p id="d1e1851">Firstly, the obstacle-surmounting dynamic model of the mechanism in rolling
mode is established. Taking the overall system of the mechanism as the
research object, the coordinate system is established at the center of the
rolling wheel. The force on the mechanism is shown in Fig. 8. Assuming
<inline-formula><mml:math id="M44" display="inline"><mml:mrow><mml:mover accent="true"><mml:mi>x</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover><mml:mo>,</mml:mo><mml:mover accent="true"><mml:mi>y</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover><mml:mo>,</mml:mo><mml:mover accent="true"><mml:mi mathvariant="italic">θ</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover></mml:mrow></mml:math></inline-formula> is the acceleration in the <inline-formula><mml:math id="M45" display="inline"><mml:mi>x</mml:mi></mml:math></inline-formula>, <inline-formula><mml:math id="M46" display="inline"><mml:mi>y</mml:mi></mml:math></inline-formula> direction and
angular acceleration of the centroid of the main body, the equations of the
force and moment are as follows:

                <disp-formula specific-use="gather" content-type="numbered"><mml:math id="M47" display="block"><mml:mtable displaystyle="true"><mml:mlabeledtr id="Ch1.E7"><mml:mtd><mml:mtext>7</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle class="stylechange" displaystyle="true"/><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>+</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mi>cos⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi><mml:mo>-</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mi>sin⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi><mml:mo>=</mml:mo><mml:mi>M</mml:mi><mml:mover accent="true"><mml:mi>x</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover></mml:mrow></mml:mtd></mml:mlabeledtr><mml:mlabeledtr id="Ch1.E8"><mml:mtd><mml:mtext>8</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle class="stylechange" displaystyle="true"/><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>+</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mi>cos⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi><mml:mo>-</mml:mo><mml:mfenced open="(" close=")"><mml:mrow><mml:mi>G</mml:mi><mml:mo>+</mml:mo><mml:msub><mml:mi>G</mml:mi><mml:mi>T</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mo>+</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mi>sin⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi><mml:mo>=</mml:mo><mml:mi>M</mml:mi><mml:mover accent="true"><mml:mi>y</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover></mml:mrow></mml:mtd></mml:mlabeledtr><mml:mlabeledtr id="Ch1.E9"><mml:mtd><mml:mtext>9</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle class="stylechange" displaystyle="true"/><mml:msub><mml:mi>T</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub><mml:mo>-</mml:mo><mml:mfenced close=")" open="("><mml:mrow><mml:mi>G</mml:mi><mml:mo>+</mml:mo><mml:msub><mml:mi>G</mml:mi><mml:mi>T</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub><mml:mo>-</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mi>H</mml:mi><mml:mo>+</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub><mml:mo>=</mml:mo><mml:mi>J</mml:mi><mml:mover accent="true"><mml:mi mathvariant="italic">θ</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover><mml:mo>,</mml:mo></mml:mrow></mml:mtd></mml:mlabeledtr></mml:mtable></mml:math></disp-formula>

            where <inline-formula><mml:math id="M48" display="inline"><mml:mrow><mml:msub><mml:mi>T</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> is driving torque of rolling wheel,
<inline-formula><mml:math id="M49" display="inline"><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula> and <inline-formula><mml:math id="M50" display="inline"><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula> are support forces of the ground and
steps acting on the rolling wheel, <inline-formula><mml:math id="M51" display="inline"><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula>, <inline-formula><mml:math id="M52" display="inline"><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula> is
frictional force of the ground and steps acting on the rolling wheel, and
<inline-formula><mml:math id="M53" display="inline"><mml:mi mathvariant="italic">β</mml:mi></mml:math></inline-formula> is the inclination angle between body and step,
<inline-formula><mml:math id="M54" display="inline"><mml:mrow><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub><mml:mo>=</mml:mo><mml:mi>R</mml:mi><mml:mi>sin⁡</mml:mi><mml:mi mathvariant="italic">α</mml:mi></mml:mrow></mml:math></inline-formula>, <inline-formula><mml:math id="M55" display="inline"><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mo>=</mml:mo><mml:mi mathvariant="italic">μ</mml:mi><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>=</mml:mo><mml:mi mathvariant="italic">μ</mml:mi><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula>.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F8"><?xmltex \currentcnt{8}?><?xmltex \def\figurename{Figure}?><label>Figure 8</label><caption><p id="d1e2231">Forces on the mechanism for roller.</p></caption>
          <?xmltex \igopts{width=213.395669pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f08.png"/>

        </fig>

      <p id="d1e2240">Assuming <inline-formula><mml:math id="M56" display="inline"><mml:mi mathvariant="italic">ψ</mml:mi></mml:math></inline-formula> is the internal friction angle, the conditions that the
mechanism does not slip at the contact point are as follows:
            <disp-formula id="Ch1.E10" content-type="numbered"><label>10</label><mml:math id="M57" display="block"><mml:mtable class="split" rowspacing="0.2ex" displaystyle="true" columnalign="right left"><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>m</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>≤</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mi>tan⁡</mml:mi><mml:mi mathvariant="italic">ψ</mml:mi><mml:mo>,</mml:mo><mml:mspace linebreak="nobreak" width="1em"/><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>m</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mo>≤</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mi>tan⁡</mml:mi><mml:mi mathvariant="italic">ψ</mml:mi><mml:mo>,</mml:mo></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mfenced close=")" open="("><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>m</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mo>-</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:mfenced><mml:mi>cos⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi><mml:mo>=</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mi>sin⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi><mml:mo>.</mml:mo></mml:mrow></mml:mtd></mml:mtr></mml:mtable></mml:math></disp-formula>
          In addition, in order to ensure that the mechanism can climb the steps, the
following conditions need to be met: <inline-formula><mml:math id="M58" display="inline"><mml:mrow><mml:mover accent="true"><mml:mi>x</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover><mml:mo>≥</mml:mo><mml:mn mathvariant="normal">0</mml:mn></mml:mrow></mml:math></inline-formula>; <inline-formula><mml:math id="M59" display="inline"><mml:mrow><mml:mover accent="true"><mml:mi>y</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover><mml:mo>≥</mml:mo><mml:mn mathvariant="normal">0</mml:mn></mml:mrow></mml:math></inline-formula>; <inline-formula><mml:math id="M60" display="inline"><mml:mrow><mml:mover accent="true"><mml:mi mathvariant="italic">θ</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover><mml:mo>≥</mml:mo><mml:mn mathvariant="normal">0</mml:mn></mml:mrow></mml:math></inline-formula>. Therefore, the driving torque of the roller can be
obtained as follows:

                <disp-formula specific-use="gather" content-type="numbered"><mml:math id="M61" display="block"><mml:mtable displaystyle="true"><mml:mlabeledtr id="Ch1.E11"><mml:mtd><mml:mtext>11</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle displaystyle="true" class="stylechange"/><mml:mtable class="split" rowspacing="0.2ex" displaystyle="true" columnalign="right left"><mml:mtr><mml:mtd><mml:mrow><mml:msub><mml:mi>T</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:mtd><mml:mtd><mml:mrow><mml:mo>≥</mml:mo><mml:mfenced open="(" close=")"><mml:mrow><mml:mi>G</mml:mi><mml:mo>+</mml:mo><mml:msub><mml:mi>G</mml:mi><mml:mi>T</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mo>+</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mrow><mml:mfenced close=")" open="("><mml:mrow><mml:mi>G</mml:mi><mml:mo>+</mml:mo><mml:msub><mml:mi>G</mml:mi><mml:mi>T</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mfenced close=")" open="("><mml:mrow><mml:mi>sin⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi><mml:mo>-</mml:mo><mml:mi mathvariant="italic">μ</mml:mi><mml:mi>cos⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi></mml:mrow></mml:mfenced><mml:mfenced open="(" close=")"><mml:mrow><mml:mi mathvariant="italic">μ</mml:mi><mml:mi>H</mml:mi><mml:mo>-</mml:mo><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:mfenced></mml:mrow><mml:mrow><mml:msup><mml:mi mathvariant="italic">μ</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msup><mml:mi>sin⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi><mml:mo>+</mml:mo><mml:mi>sin⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi></mml:mrow></mml:mfrac></mml:mstyle></mml:mrow></mml:mtd></mml:mtr></mml:mtable></mml:mrow></mml:mtd></mml:mlabeledtr><mml:mlabeledtr id="Ch1.E12"><mml:mtd><mml:mtext>12</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle class="stylechange" displaystyle="true"/><mml:mtable rowspacing="0.2ex" class="split" displaystyle="true" columnalign="right left"><mml:mtr><mml:mtd><mml:mrow><mml:msub><mml:mi>T</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:mtd><mml:mtd><mml:mrow><mml:mo>≤</mml:mo><mml:mfenced open="(" close=")"><mml:mrow><mml:mi>G</mml:mi><mml:mo>+</mml:mo><mml:msub><mml:mi>G</mml:mi><mml:mi>T</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mo>+</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mrow><mml:mfenced open="(" close=")"><mml:mrow><mml:mi>G</mml:mi><mml:mo>+</mml:mo><mml:msub><mml:mi>G</mml:mi><mml:mi>T</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mfenced open="(" close=")"><mml:mrow><mml:mi>sin⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi><mml:mo>-</mml:mo><mml:mi>tan⁡</mml:mi><mml:mi mathvariant="italic">ψ</mml:mi><mml:mi>cos⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi></mml:mrow></mml:mfenced><mml:mfenced close=")" open="("><mml:mrow><mml:mi>H</mml:mi><mml:mi>tan⁡</mml:mi><mml:mi mathvariant="italic">ψ</mml:mi><mml:mo>-</mml:mo><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:mfenced></mml:mrow><mml:mrow><mml:mi>sin⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi><mml:mo>+</mml:mo><mml:mi mathvariant="italic">μ</mml:mi><mml:mi>tan⁡</mml:mi><mml:mi mathvariant="italic">ψ</mml:mi><mml:mi>sin⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi></mml:mrow></mml:mfrac></mml:mstyle><mml:mo>,</mml:mo></mml:mrow></mml:mtd></mml:mtr></mml:mtable></mml:mrow></mml:mtd></mml:mlabeledtr></mml:mtable></mml:math></disp-formula>

            where  <inline-formula><mml:math id="M62" display="inline"><mml:mrow><mml:mn mathvariant="normal">0</mml:mn><mml:mo>≤</mml:mo><mml:mi mathvariant="italic">β</mml:mi><mml:mo>≤</mml:mo><mml:mi>arctan⁡</mml:mi><mml:mo>(</mml:mo><mml:mi>tan⁡</mml:mi><mml:mi mathvariant="italic">ψ</mml:mi><mml:mo>-</mml:mo><mml:mi mathvariant="italic">μ</mml:mi><mml:mo>)</mml:mo></mml:mrow></mml:math></inline-formula>.</p>
      <p id="d1e2639">According to the geometric relationship in Fig. 8, the height range of the
mechanism that can climb steps is <inline-formula><mml:math id="M63" display="inline"><mml:mrow><mml:mn mathvariant="normal">0</mml:mn><mml:mo>≤</mml:mo><mml:mi>H</mml:mi><mml:mo>≤</mml:mo><mml:mi>R</mml:mi><mml:mo>-</mml:mo><mml:mi>R</mml:mi><mml:mi>cos⁡</mml:mi><mml:mi mathvariant="italic">β</mml:mi></mml:mrow></mml:math></inline-formula>. Let
<inline-formula><mml:math id="M64" display="inline"><mml:mrow><mml:mi mathvariant="italic">ψ</mml:mi><mml:mo>=</mml:mo><mml:mn mathvariant="normal">35</mml:mn></mml:mrow></mml:math></inline-formula><inline-formula><mml:math id="M65" display="inline"><mml:msup><mml:mi/><mml:mo>∘</mml:mo></mml:msup></mml:math></inline-formula>, <inline-formula><mml:math id="M66" display="inline"><mml:mrow><mml:mi mathvariant="italic">μ</mml:mi><mml:mo>=</mml:mo><mml:mn mathvariant="normal">0.1</mml:mn></mml:mrow></mml:math></inline-formula>. The stable boundary line when rolling over
the steps is shown in Fig. 9. It is shown that when the inclination angle of
the mechanism increases, the height of the rolling climbing step increases,
and the driving torque of the wheels also increases. According to the
constraint condition that no slip occurs, the maximum inclination of the
mechanism can be obtained as 54.28<inline-formula><mml:math id="M67" display="inline"><mml:msup><mml:mi/><mml:mo>∘</mml:mo></mml:msup></mml:math></inline-formula>, thus the maximum climbing
height of roll-over mode can be obtained as 87.36 mm.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F9"><?xmltex \currentcnt{9}?><?xmltex \def\figurename{Figure}?><label>Figure 9</label><caption><p id="d1e2709">Stable boundary line during rolling climbing.</p></caption>
          <?xmltex \igopts{width=213.395669pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f09.png"/>

        </fig>

      <p id="d1e2718">Secondly, dynamic model of obstacle-crossing mode using support legs is
established. The force on the mechanism is shown in Fig. 10. According to
the geometric relationship, it can be obtained that the height range of
support leg climbing steps is as follows:
            <disp-formula id="Ch1.E13" content-type="numbered"><label>13</label><mml:math id="M68" display="block"><mml:mrow><mml:mn mathvariant="normal">87.36</mml:mn><mml:mspace linebreak="nobreak" width="0.125em"/><mml:mi mathvariant="normal">mm</mml:mi><mml:mo>≤</mml:mo><mml:mi>H</mml:mi><mml:mo>≤</mml:mo><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">0</mml:mn></mml:msub><mml:mi>cos⁡</mml:mi><mml:mfenced open="(" close=")"><mml:mrow><mml:msub><mml:mi mathvariant="italic">α</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mo>-</mml:mo><mml:mi mathvariant="italic">π</mml:mi><mml:mo>/</mml:mo><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:mfenced><mml:mo>-</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mrow><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msub></mml:mrow><mml:mrow><mml:mi>tan⁡</mml:mi><mml:mfenced open="(" close=")"><mml:mrow><mml:mi mathvariant="italic">π</mml:mi><mml:mo>/</mml:mo><mml:mn mathvariant="normal">2</mml:mn><mml:mo>-</mml:mo><mml:msub><mml:mi mathvariant="italic">φ</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced></mml:mrow></mml:mfrac></mml:mstyle><mml:mo>.</mml:mo></mml:mrow></mml:math></disp-formula>
          The equations of the force and moment are as follows:

                <disp-formula specific-use="gather" content-type="numbered"><mml:math id="M69" display="block"><mml:mtable displaystyle="true"><mml:mlabeledtr id="Ch1.E14"><mml:mtd><mml:mtext>14</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle class="stylechange" displaystyle="true"/><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>+</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mi>cos⁡</mml:mi><mml:mfenced close=")" open="("><mml:mrow><mml:mi mathvariant="italic">π</mml:mi><mml:mo>/</mml:mo><mml:mn mathvariant="normal">2</mml:mn><mml:mo>-</mml:mo><mml:msub><mml:mi mathvariant="italic">φ</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mo>-</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mi>sin⁡</mml:mi><mml:mfenced close=")" open="("><mml:mrow><mml:mi mathvariant="italic">π</mml:mi><mml:mo>/</mml:mo><mml:mn mathvariant="normal">2</mml:mn><mml:mo>-</mml:mo><mml:msub><mml:mi mathvariant="italic">φ</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mo>=</mml:mo><mml:mi>M</mml:mi><mml:mover accent="true"><mml:mi>x</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover></mml:mrow></mml:mtd></mml:mlabeledtr><mml:mlabeledtr id="Ch1.E15"><mml:mtd><mml:mtext>15</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle class="stylechange" displaystyle="true"/><mml:mtable rowspacing="0.2ex" class="split" displaystyle="true" columnalign="right left"><mml:mtr><mml:mtd><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:mtd><mml:mtd><mml:mrow><mml:mo>+</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mi>cos⁡</mml:mi><mml:mfenced close=")" open="("><mml:mrow><mml:mi mathvariant="italic">π</mml:mi><mml:mo>/</mml:mo><mml:mn mathvariant="normal">2</mml:mn><mml:mo>-</mml:mo><mml:msub><mml:mi mathvariant="italic">φ</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mo>+</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:msub><mml:mi>sin⁡</mml:mi><mml:mfenced open="(" close=")"><mml:mrow><mml:mi mathvariant="italic">π</mml:mi><mml:mo>/</mml:mo><mml:mn mathvariant="normal">2</mml:mn><mml:mo>-</mml:mo><mml:msub><mml:mi mathvariant="italic">φ</mml:mi><mml:mi>k</mml:mi></mml:msub></mml:mrow></mml:mfenced></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mo>-</mml:mo><mml:mi>G</mml:mi><mml:mo>-</mml:mo><mml:msub><mml:mi>G</mml:mi><mml:mi>T</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mi>M</mml:mi><mml:mover accent="true"><mml:mi>y</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover></mml:mrow></mml:mtd></mml:mtr></mml:mtable></mml:mrow></mml:mtd></mml:mlabeledtr><mml:mlabeledtr id="Ch1.E16"><mml:mtd><mml:mtext>16</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle displaystyle="true" class="stylechange"/><mml:mtable rowspacing="0.2ex" class="split" displaystyle="true" columnalign="right left"><mml:mtr><mml:mtd><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:mtd><mml:mtd><mml:mrow><mml:mo>-</mml:mo><mml:msub><mml:mi>G</mml:mi><mml:mi>T</mml:mi></mml:msub><mml:mo>×</mml:mo><mml:mfenced open="[" close="]"><mml:mrow><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub><mml:mo>-</mml:mo><mml:mfenced open="(" close=")"><mml:mrow><mml:msub><mml:mi>l</mml:mi><mml:mrow><mml:mi>s</mml:mi><mml:mi>k</mml:mi></mml:mrow></mml:msub><mml:mo>-</mml:mo><mml:mi>R</mml:mi></mml:mrow></mml:mfenced><mml:mo>/</mml:mo><mml:mn mathvariant="normal">2</mml:mn><mml:mo>×</mml:mo><mml:mi>sin⁡</mml:mi><mml:mfenced close=")" open="("><mml:mrow><mml:msub><mml:mi mathvariant="italic">α</mml:mi><mml:mi>k</mml:mi></mml:msub><mml:mo>-</mml:mo><mml:mi mathvariant="italic">π</mml:mi><mml:mo>/</mml:mo><mml:mn mathvariant="normal">2</mml:mn></mml:mrow></mml:mfenced></mml:mrow></mml:mfenced></mml:mrow></mml:mtd></mml:mtr><mml:mtr><mml:mtd/><mml:mtd><mml:mrow><mml:mo>-</mml:mo><mml:mi>G</mml:mi><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msub><mml:mo>-</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>f</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mi>H</mml:mi><mml:mo>=</mml:mo><mml:mi>J</mml:mi><mml:mover accent="true"><mml:mi mathvariant="italic">θ</mml:mi><mml:mo mathvariant="normal">¨</mml:mo></mml:mover><mml:mo>.</mml:mo></mml:mrow></mml:mtd></mml:mtr></mml:mtable></mml:mrow></mml:mtd></mml:mlabeledtr></mml:mtable></mml:math></disp-formula>

            Let the height of the step be <inline-formula><mml:math id="M70" display="inline"><mml:mrow><mml:mi>H</mml:mi><mml:mo>=</mml:mo><mml:mn mathvariant="normal">100</mml:mn></mml:mrow></mml:math></inline-formula> mm, the variation of force on the
mechanism during climbing is shown in Fig. 11. It is shown that support force
of the ground on the leg decreases with the increase of climbing height.
When the climbing height is greater than 80 mm, the supporting force drops
sharply. However, the supporting force of the steps on the main body
increases with the increase of climbing height. When support leg 1 is
switched to support leg 2, the supporting force and frictional force
gradually increases or decreases. When support leg 2 is switched to support
leg 3, the supporting force and frictional force change abruptly.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F10"><?xmltex \currentcnt{10}?><?xmltex \def\figurename{Figure}?><label>Figure 10</label><caption><p id="d1e3107">Forces on the mechanism for support legs.</p></caption>
          <?xmltex \igopts{width=170.716535pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f10.png"/>

        </fig>

      <?xmltex \floatpos{t}?><fig id="Ch1.F11"><?xmltex \currentcnt{11}?><?xmltex \def\figurename{Figure}?><label>Figure 11</label><caption><p id="d1e3118">The variation of force during climbing.</p></caption>
          <?xmltex \igopts{width=199.169291pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f11.png"/>

        </fig>

      <?xmltex \floatpos{t}?><fig id="Ch1.F12" specific-use="star"><?xmltex \currentcnt{12}?><?xmltex \def\figurename{Figure}?><label>Figure 12</label><caption><p id="d1e3129">The variation of support force acting on support leg.​​​​​​​</p></caption>
          <?xmltex \igopts{width=497.923228pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f12.png"/>

        </fig>

      <?xmltex \floatpos{t}?><fig id="Ch1.F13" specific-use="star"><?xmltex \currentcnt{13}?><?xmltex \def\figurename{Figure}?><label>Figure 13</label><caption><p id="d1e3140">The variation of support force of steps on the main body.</p></caption>
          <?xmltex \igopts{width=497.923228pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f13.png"/>

        </fig>

      <p id="d1e3150">The supporting force of the ground on the leg changes with the rolling angle
and contact angle, as shown in Fig. 12. It is shown that for the same support
leg, the support force decreases with the increase of the rolling angle of
the main body, while the change of the contact angle has little effect on
the support force. When the rolling angle is 84.3<inline-formula><mml:math id="M71" display="inline"><mml:msup><mml:mi/><mml:mo>∘</mml:mo></mml:msup></mml:math></inline-formula>, the support
force on the leg is close to 0, and the wheel–leg deformation mechanism
turns over the step. The supporting force of the step on the main body
varies with the rolling angle and contact angle, as shown in Fig. 13. It is
shown that the support force of the step increases with the increase of the
rolling angle of the main body, and when the rolling angle is greater than
70<inline-formula><mml:math id="M72" display="inline"><mml:msup><mml:mi/><mml:mo>∘</mml:mo></mml:msup></mml:math></inline-formula>, the support force increases sharply.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F14" specific-use="star"><?xmltex \currentcnt{14}?><?xmltex \def\figurename{Figure}?><label>Figure 14</label><caption><p id="d1e3173">The variation of the torque with rolling angle and
contact angle.</p></caption>
          <?xmltex \igopts{width=497.923228pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f14.png"/>

        </fig>

      <p id="d1e3182">Let driving torque <inline-formula><mml:math id="M73" display="inline"><mml:mrow><mml:msub><mml:mi>T</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msub><mml:mo>=</mml:mo><mml:mfenced close=")" open="("><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>N</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>-</mml:mo><mml:msub><mml:mi>G</mml:mi><mml:mi>T</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:msub><mml:mi>L</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula>, the driving torque changes with the rolling angle and contact
angle, as shown in Fig. 14. It is shown that the driving torque decreases
with the increase of the rolling angle of the main body. That is to say,
when the wheel–leg deformation mechanism climbs over the steps, the driving
torque required is gradually reduced, and finally the climbing can be
completed with the help of gravity.</p><?xmltex \hack{\newpage}?>
</sec>
<sec id="Ch1.S3.SS3">
  <label>3.3</label><title>Analysis of tipping stability during obstacle crossing</title>
      <p id="d1e3230">The wheel–leg deformation mechanism is often disturbed by external forces,
environment, and other external factors when walking over obstacles, and may
overturn. Therefore, the stability cone method is used to comprehensively
evaluate the static and dynamic stability of the side line tipping and
corner tipping of the wheel–leg deformation mechanism, in order to ensure the
normal operation of the mechanism. The centroid <inline-formula><mml:math id="M74" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">0</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> of the fuselage is taken as the apex of the stability cone, and the
contact points <inline-formula><mml:math id="M75" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> (<inline-formula><mml:math id="M76" display="inline"><mml:mrow><mml:mi>i</mml:mi><mml:mo>=</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:math></inline-formula>, … 3) between the
deformation mechanism and the obstacle and the ground are regarded as the
corners of the stabilizing cone. The coordinate system is established on the
stable cone, take <inline-formula><mml:math id="M77" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">0</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> as the origin, the vertical direction is the <inline-formula><mml:math id="M78" display="inline"><mml:mi>z</mml:mi></mml:math></inline-formula> axis, and the direction of mechanism movement is the <inline-formula><mml:math id="M79" display="inline"><mml:mi>x</mml:mi></mml:math></inline-formula> axis. The <inline-formula><mml:math id="M80" display="inline"><mml:mi>y</mml:mi></mml:math></inline-formula> axis is gotten by the right-hand rule. The stability cone model is shown in Fig. 15.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F15"><?xmltex \currentcnt{15}?><?xmltex \def\figurename{Figure}?><label>Figure 15</label><caption><p id="d1e3302">A stable cone model of leg obstacle walking.</p></caption>
          <?xmltex \igopts{width=241.848425pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f15.png"/>

        </fig>

      <p id="d1e3311">Assuming the vectors of contact points between the left and right rolling
wheels and the obstacle are <inline-formula><mml:math id="M81" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> and <inline-formula><mml:math id="M82" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">3</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula>, and the contact points between the support leg and the ground are <inline-formula><mml:math id="M83" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula>. The normal vector <inline-formula><mml:math id="M84" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="bold-italic">l</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> of the tipping edge line <inline-formula><mml:math id="M85" display="inline"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> is as follows:</p>
      <p id="d1e3370"><?xmltex \hack{\newpage}?>

                <disp-formula specific-use="gather" content-type="numbered"><mml:math id="M86" display="block"><mml:mtable displaystyle="true"><mml:mlabeledtr id="Ch1.E17"><mml:mtd><mml:mtext>17</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle class="stylechange" displaystyle="true"/><mml:msub><mml:mi mathvariant="bold-italic">l</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mfenced open="(" close=")"><mml:mrow><mml:mi mathvariant="bold">I</mml:mi><mml:mo>-</mml:mo><mml:msub><mml:mover accent="true"><mml:mi>a</mml:mi><mml:mo mathvariant="normal" stretchy="false">^</mml:mo></mml:mover><mml:mi>i</mml:mi></mml:msub><mml:msubsup><mml:mover accent="true"><mml:mi>a</mml:mi><mml:mo stretchy="false" mathvariant="normal">^</mml:mo></mml:mover><mml:mi>i</mml:mi><mml:mi>T</mml:mi></mml:msubsup></mml:mrow></mml:mfenced><mml:msub><mml:mi>P</mml:mi><mml:mrow><mml:mi>i</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mspace linebreak="nobreak" width="1em"/><mml:mo>(</mml:mo><mml:mi>i</mml:mi><mml:mo>=</mml:mo><mml:mn mathvariant="normal">1</mml:mn><mml:mo>,</mml:mo><mml:mi mathvariant="normal">…</mml:mi><mml:mi>n</mml:mi><mml:mo>)</mml:mo><mml:mo>,</mml:mo><mml:mspace width="1em" linebreak="nobreak"/><mml:msub><mml:mi>P</mml:mi><mml:mrow><mml:mi>n</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:mtd></mml:mlabeledtr><mml:mlabeledtr id="Ch1.E18"><mml:mtd><mml:mtext>18</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle displaystyle="true" class="stylechange"/><mml:msub><mml:mi>a</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi>P</mml:mi><mml:mrow><mml:mi>i</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>-</mml:mo><mml:msub><mml:mi>P</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mspace width="1em" linebreak="nobreak"/><mml:mfenced close=")" open="("><mml:mrow><mml:mi>i</mml:mi><mml:mo>=</mml:mo><mml:mn mathvariant="normal">1</mml:mn><mml:mo>,</mml:mo><mml:mi mathvariant="normal">…</mml:mi><mml:mi>n</mml:mi><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:mfenced><mml:mo>,</mml:mo><mml:mspace linebreak="nobreak" width="1em"/><mml:msub><mml:mi>a</mml:mi><mml:mi>n</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub><mml:mo>-</mml:mo><mml:msub><mml:mi>P</mml:mi><mml:mi>n</mml:mi></mml:msub></mml:mrow></mml:mtd></mml:mlabeledtr><mml:mlabeledtr id="Ch1.E19"><mml:mtd><mml:mtext>19</mml:mtext></mml:mtd><mml:mtd><mml:mrow><mml:mstyle class="stylechange" displaystyle="true"/><mml:msub><mml:mover accent="true"><mml:mi>a</mml:mi><mml:mo stretchy="false" mathvariant="normal">^</mml:mo></mml:mover><mml:mi>i</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi>a</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>/</mml:mo><mml:mfenced close="∥" open="∥"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mo>,</mml:mo></mml:mrow></mml:mtd></mml:mlabeledtr></mml:mtable></mml:math></disp-formula>

            where <inline-formula><mml:math id="M87" display="inline"><mml:mi mathvariant="bold">I</mml:mi></mml:math></inline-formula> is identity matrix.</p>
      <p id="d1e3579">In the process of obstacle crossing, it is assumed that the total external
force received by the mechanism is <inline-formula><mml:math id="M88" display="inline"><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mi>r</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>, and the total external moment
received by the mass center of the main body is <inline-formula><mml:math id="M89" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">τ</mml:mi><mml:mi>r</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>. The equivalent
force <inline-formula><mml:math id="M90" display="inline"><mml:mrow><mml:msubsup><mml:mi>F</mml:mi><mml:mi>i</mml:mi><mml:mo>∗</mml:mo></mml:msubsup></mml:mrow></mml:math></inline-formula> of the total external force <inline-formula><mml:math id="M91" display="inline"><mml:mrow><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>r</mml:mi><mml:mi>i</mml:mi></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula>, and the total external moment <inline-formula><mml:math id="M92" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">τ</mml:mi><mml:mrow><mml:mi>r</mml:mi><mml:mi>i</mml:mi></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula> acting on the tipping edge line <inline-formula><mml:math id="M93" display="inline"><mml:mi>i</mml:mi></mml:math></inline-formula> is as follows:
            <disp-formula id="Ch1.E20" content-type="numbered"><label>20</label><mml:math id="M94" display="block"><mml:mrow><mml:msubsup><mml:mi>F</mml:mi><mml:mi>i</mml:mi><mml:mo>∗</mml:mo></mml:msubsup><mml:mo>=</mml:mo><mml:msub><mml:mi>F</mml:mi><mml:mrow><mml:mi>r</mml:mi><mml:mi>i</mml:mi></mml:mrow></mml:msub><mml:mo>+</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mrow><mml:msub><mml:mi mathvariant="bold-italic">l</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow><mml:mrow><mml:msup><mml:mfenced close="∥" open="∥"><mml:mrow><mml:msub><mml:mi mathvariant="bold-italic">l</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mn mathvariant="normal">2</mml:mn></mml:msup></mml:mrow></mml:mfrac></mml:mstyle><mml:msub><mml:mi mathvariant="italic">τ</mml:mi><mml:mrow><mml:mi>r</mml:mi><mml:mi>i</mml:mi></mml:mrow></mml:msub><mml:mo>.</mml:mo></mml:mrow></mml:math></disp-formula>
          When the wheel–leg deformation mechanism is under the action of equal
force, the tipping angle of the sideline <inline-formula><mml:math id="M95" display="inline"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> is defined as the
angle <inline-formula><mml:math id="M96" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">γ</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>, which is the angle between the equal force
<inline-formula><mml:math id="M97" display="inline"><mml:mrow><mml:msubsup><mml:mi>F</mml:mi><mml:mi>i</mml:mi><mml:mo>∗</mml:mo></mml:msubsup></mml:mrow></mml:math></inline-formula> and the normal <inline-formula><mml:math id="M98" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="bold-italic">l</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>. The
tipping angle of the stable cone corner is defined as the angle <inline-formula><mml:math id="M99" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">ϕ</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>, which is the angle between the equal force <inline-formula><mml:math id="M100" display="inline"><mml:mrow><mml:msubsup><mml:mi>F</mml:mi><mml:mi>i</mml:mi><mml:mo>∗</mml:mo></mml:msubsup></mml:mrow></mml:math></inline-formula> and
<inline-formula><mml:math id="M101" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula>. The angle <inline-formula><mml:math id="M102" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">γ</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> and the angle <inline-formula><mml:math id="M103" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">ϕ</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> can be obtained by the following formula:
            <disp-formula id="Ch1.E21" content-type="numbered"><label>21</label><mml:math id="M104" display="block"><mml:mrow><mml:msub><mml:mi mathvariant="italic">γ</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi mathvariant="italic">σ</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mi>arccos⁡</mml:mi><mml:mfenced open="(" close=")"><mml:mrow><mml:msubsup><mml:mover accent="true"><mml:mi>F</mml:mi><mml:mo mathvariant="normal" stretchy="false">^</mml:mo></mml:mover><mml:mi>i</mml:mi><mml:mo>∗</mml:mo></mml:msubsup><mml:mo>⋅</mml:mo><mml:msub><mml:mover accent="true"><mml:mi>l</mml:mi><mml:mo stretchy="false" mathvariant="normal">^</mml:mo></mml:mover><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mo>,</mml:mo><mml:mspace linebreak="nobreak" width="1em"/><mml:msub><mml:mi mathvariant="italic">ϕ</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:msub><mml:mi mathvariant="italic">σ</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mi>arccos⁡</mml:mi><mml:mfenced close=")" open="("><mml:mrow><mml:msubsup><mml:mover accent="true"><mml:mi>F</mml:mi><mml:mo stretchy="false" mathvariant="normal">^</mml:mo></mml:mover><mml:mi>i</mml:mi><mml:mo>∗</mml:mo></mml:msubsup><mml:mo>⋅</mml:mo><mml:msub><mml:mover accent="true"><mml:mi>P</mml:mi><mml:mo stretchy="false" mathvariant="normal">^</mml:mo></mml:mover><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:mfenced><mml:mo>,</mml:mo></mml:mrow></mml:math></disp-formula>
          where <inline-formula><mml:math id="M105" display="inline"><mml:mrow><mml:msubsup><mml:mover accent="true"><mml:mi>F</mml:mi><mml:mo stretchy="false" mathvariant="normal">^</mml:mo></mml:mover><mml:mi>i</mml:mi><mml:mo>∗</mml:mo></mml:msubsup><mml:mo>=</mml:mo><mml:msubsup><mml:mi>F</mml:mi><mml:mi>i</mml:mi><mml:mo>∗</mml:mo></mml:msubsup><mml:mo>/</mml:mo><mml:mfenced close="∥" open="∥"><mml:mrow><mml:msubsup><mml:mi>F</mml:mi><mml:mi>i</mml:mi><mml:mo>∗</mml:mo></mml:msubsup></mml:mrow></mml:mfenced></mml:mrow></mml:math></inline-formula>, when <inline-formula><mml:math id="M106" display="inline"><mml:mrow><mml:mo>(</mml:mo><mml:msubsup><mml:mover accent="true"><mml:mi>F</mml:mi><mml:mo mathvariant="normal" stretchy="false">^</mml:mo></mml:mover><mml:mi>i</mml:mi><mml:mo>∗</mml:mo></mml:msubsup><mml:mo>×</mml:mo><mml:msub><mml:mover accent="true"><mml:mi>l</mml:mi><mml:mo stretchy="false" mathvariant="normal">^</mml:mo></mml:mover><mml:mi>i</mml:mi></mml:msub><mml:mo>)</mml:mo><mml:mo>⋅</mml:mo><mml:msub><mml:mi>a</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>&lt;</mml:mo><mml:mn mathvariant="normal">0</mml:mn></mml:mrow></mml:math></inline-formula>, <inline-formula><mml:math id="M107" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">σ</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:math></inline-formula>. Otherwise, <inline-formula><mml:math id="M108" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">σ</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mo>-</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:math></inline-formula>.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F16" specific-use="star"><?xmltex \currentcnt{16}?><?xmltex \def\figurename{Figure}?><label>Figure 16</label><caption><p id="d1e4007">Stability analysis without interference force.</p></caption>
          <?xmltex \igopts{width=384.112205pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f16.png"/>

        </fig>

      <p id="d1e4016">Considering the global stability of the system, let <inline-formula><mml:math id="M109" display="inline"><mml:mrow><mml:msub><mml:mi mathvariant="italic">θ</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mo>min⁡</mml:mo><mml:mo>(</mml:mo><mml:msub><mml:mi mathvariant="italic">γ</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>,</mml:mo><mml:msub><mml:mi mathvariant="italic">ϕ</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>,</mml:mo><mml:msub><mml:mi mathvariant="italic">ϕ</mml:mi><mml:mrow><mml:mi>i</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub><mml:mo>)</mml:mo></mml:mrow></mml:math></inline-formula>, then the minimum
stability angle of the whole system is
            <disp-formula id="Ch1.E22" content-type="numbered"><label>22</label><mml:math id="M110" display="block"><mml:mrow><mml:msub><mml:mi mathvariant="italic">θ</mml:mi><mml:mi mathvariant="normal">s</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mo movablelimits="false">min⁡</mml:mo><mml:mo>(</mml:mo><mml:msub><mml:mi mathvariant="italic">θ</mml:mi><mml:mi>i</mml:mi></mml:msub><mml:mo>)</mml:mo><mml:mo>.</mml:mo></mml:mrow></mml:math></disp-formula>
          Comprehensively considering the side line tipping angle and corner tipping
angle, the stability index of the wheel–leg deformation mechanism is
            <disp-formula id="Ch1.E23" content-type="numbered"><label>23</label><mml:math id="M111" display="block"><mml:mrow><mml:msub><mml:mi>S</mml:mi><mml:mi mathvariant="normal">d</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mo movablelimits="false">max⁡</mml:mo><mml:mfenced close=")" open="("><mml:mrow><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mn mathvariant="normal">1</mml:mn><mml:mrow><mml:msub><mml:mi mathvariant="italic">γ</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:mfrac></mml:mstyle><mml:mo>+</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mn mathvariant="normal">1</mml:mn><mml:mrow><mml:msub><mml:mi mathvariant="italic">ϕ</mml:mi><mml:mi>i</mml:mi></mml:msub></mml:mrow></mml:mfrac></mml:mstyle><mml:mo>+</mml:mo><mml:mstyle displaystyle="true"><mml:mfrac style="display"><mml:mn mathvariant="normal">1</mml:mn><mml:mrow><mml:msub><mml:mi mathvariant="italic">ϕ</mml:mi><mml:mrow><mml:mi>i</mml:mi><mml:mo>+</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:msub></mml:mrow></mml:mfrac></mml:mstyle></mml:mrow></mml:mfenced><mml:mo>.</mml:mo></mml:mrow></mml:math></disp-formula>
          Without interference, the stability analysis results of the wheel–leg
deformation mechanism are shown in Fig. 16. When support leg 1 works, the
change of side line tipping angle and corner tipping angle with time is
shown in Fig. 16a. It is shown that because of the symmetry of the
structure, the tipping angles of the sidelines <inline-formula><mml:math id="M112" display="inline"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> and
<inline-formula><mml:math id="M113" display="inline"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> are the same, and the corner <inline-formula><mml:math id="M114" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> and <inline-formula><mml:math id="M115" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">3</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> have the same
tipping angle. The tipping angles of side line <inline-formula><mml:math id="M116" display="inline"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mn mathvariant="normal">3</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula>,
corner <inline-formula><mml:math id="M117" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula>, and <inline-formula><mml:math id="M118" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">3</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> decrease with
time. However, the tipping angle of the corner <inline-formula><mml:math id="M119" display="inline"><mml:mrow><mml:msub><mml:mi>P</mml:mi><mml:mn mathvariant="normal">3</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> increases with time. When support leg 2 works, the change of side line
tipping angle and corner tipping angle with time is shown in Fig. 16b. It
is shown that the tipping angle of sidelines <inline-formula><mml:math id="M120" display="inline"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mn mathvariant="normal">1</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> and
<inline-formula><mml:math id="M121" display="inline"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mn mathvariant="normal">2</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> increases with time. The change of the tipping
angle of the other sidelines and corners with time is similar to that of the
support leg 1. When support leg 3 works, the change of side line tipping
angle and corner tipping angle with time is shown in Fig. 16c. It is
shown that the tipping angle of side line <inline-formula><mml:math id="M122" display="inline"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mn mathvariant="normal">3</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> gradually
approaches 0<inline-formula><mml:math id="M123" display="inline"><mml:msup><mml:mi/><mml:mo>∘</mml:mo></mml:msup></mml:math></inline-formula> with the increase of time, and the tipping angles of
other side lines and corners change little with time. The change of stability
index with time during the climbing process of the wheel–leg deformation
mechanism is shown in Fig. 16d. It is shown that when support leg 1 and
support leg 2 work, the system is relatively stable. When the support leg 3
works, the system becomes extremely unstable. When <inline-formula><mml:math id="M124" display="inline"><mml:mrow><mml:mi>t</mml:mi><mml:mo>=</mml:mo><mml:mn mathvariant="normal">2.95</mml:mn></mml:mrow></mml:math></inline-formula> s, the whole
mechanism overturns along the side line <inline-formula><mml:math id="M125" display="inline"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mn mathvariant="normal">3</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula>; that is,
the whole mechanism crosses the step.</p>

      <?xmltex \floatpos{t}?><fig id="Ch1.F17" specific-use="star"><?xmltex \currentcnt{17}?><?xmltex \def\figurename{Figure}?><label>Figure 17</label><caption><p id="d1e4303">Stability analysis under disturbing force.</p></caption>
          <?xmltex \igopts{width=398.338583pt}?><graphic xlink:href="https://ms.copernicus.org/articles/14/1/2023/ms-14-1-2023-f17.png"/>

        </fig>

      <p id="d1e4313">To test the anti-interference ability of the wheel–leg deformation
mechanism, the interference force is applied in the positive and negative
directions along the <inline-formula><mml:math id="M126" display="inline"><mml:mi>x</mml:mi></mml:math></inline-formula> axis, the positive direction of the <inline-formula><mml:math id="M127" display="inline"><mml:mi>y</mml:mi></mml:math></inline-formula> axis, and the positive direction of the <inline-formula><mml:math id="M128" display="inline"><mml:mi>z</mml:mi></mml:math></inline-formula> axis, respectively. Note that because the roller is symmetrical to the center of mass, the interference effect in the
positive and negative directions of <inline-formula><mml:math id="M129" display="inline"><mml:mi>y</mml:mi></mml:math></inline-formula> axis is the same, so only the
interference force in the positive direction of <inline-formula><mml:math id="M130" display="inline"><mml:mi>y</mml:mi></mml:math></inline-formula> axis is discussed. The
interference effect in the negative direction of the <inline-formula><mml:math id="M131" display="inline"><mml:mi>z</mml:mi></mml:math></inline-formula> axis is the same as
that of gravity, and the overturning stability is similar to that without
interference. Therefore, only the interference force in the positive
direction of the <inline-formula><mml:math id="M132" display="inline"><mml:mi>z</mml:mi></mml:math></inline-formula> axis is discussed. Let <inline-formula><mml:math id="M133" display="inline"><mml:mrow><mml:msub><mml:mover accent="true"><mml:mi>F</mml:mi><mml:mo stretchy="false" mathvariant="normal">^</mml:mo></mml:mover><mml:mi>x</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mo>±</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:math></inline-formula>, <inline-formula><mml:math id="M134" display="inline"><mml:mrow><mml:msub><mml:mover accent="true"><mml:mi>F</mml:mi><mml:mo mathvariant="normal" stretchy="false">^</mml:mo></mml:mover><mml:mi>y</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:math></inline-formula>, and <inline-formula><mml:math id="M135" display="inline"><mml:mrow><mml:msub><mml:mover accent="true"><mml:mi>F</mml:mi><mml:mo stretchy="false" mathvariant="normal">^</mml:mo></mml:mover><mml:mi>z</mml:mi></mml:msub><mml:mo>=</mml:mo><mml:mn mathvariant="normal">1</mml:mn></mml:mrow></mml:math></inline-formula>, the change of the minimum stability angle of
the system with time is shown in Fig. 17a. It is shown that the minimum
stability angle will jump when the support legs alternate. When the
disturbing force is applied along the positive direction of the <inline-formula><mml:math id="M136" display="inline"><mml:mi>x</mml:mi></mml:math></inline-formula> axis and
the positive direction of the <inline-formula><mml:math id="M137" display="inline"><mml:mi>z</mml:mi></mml:math></inline-formula> axis, the minimum stability angle will
increase with time. When the disturbing force is applied along the negative
direction of the <inline-formula><mml:math id="M138" display="inline"><mml:mi>x</mml:mi></mml:math></inline-formula> axis and the positive direction of the <inline-formula><mml:math id="M139" display="inline"><mml:mi>y</mml:mi></mml:math></inline-formula> axis, the minimum
stability angle will decrease with time. The change of the stability index
of the system with time is shown in Fig. 17b. It is shown that when the
disturbing force is applied along the positive direction of the <inline-formula><mml:math id="M140" display="inline"><mml:mi>x</mml:mi></mml:math></inline-formula> axis, the
stability index will decrease with time. Other disturbing forces have little
change with time. The existence of interference force has little influence
on the stability of the system. This shows that the mechanism has good
anti-interference ability.</p>
</sec>
</sec>
<sec id="Ch1.S4" sec-type="conclusions">
  <label>4</label><title>Conclusion</title>
      <p id="d1e4467">In this paper, a wheel–leg deformation mechanism suitable for a complex road
environment is designed. The switching principle of the wheels and legs,
gait planning for leg-type obstacle-crossing, obstacle-climbing performance,
and rollover stability are discussed. Combining theoretical analysis and
dynamics simulation, the rationality of the wheel–leg deformation mechanism
design and the feasibility of leg-type obstacle-crossing walking are
verified. The main conclusions are as follows:
<list list-type="order"><list-item>
      <p id="d1e4472">A new type of wheel–leg deformation mechanism based on gear
transmission is proposed. The mechanism has high maneuverability of wheel
rolling and high adaptability of leg obstacle climbing. When the road
surface is flat, the roller mode is used to achieve fast forward speed. When encountering unstructured terrain such as steps and gullies, the support leg mode can be switched by the electromagnetic clutch to complete obstacle crossing.</p></list-item><list-item>
      <p id="d1e4476">The gait of support legs is planned and the kinematics characteristics
of the mechanism are studied. It is shown that the wheel–leg deformation
mechanism can surmount obstacles through alternate support of contact feet.
The alternation of the support legs does not affect the smooth climbing of
the mechanism, but will cause the step change of the angular velocity of the centroid. Different support legs have different initial contact angles which increase with the extension of the leg.</p></list-item><list-item>
      <p id="d1e4480">The obstacle-surmounting performance of roll-over mode and obstacle-crossing mode using support legs are analyzed. For roll-over mode, when the
inclination angle of the mechanism increases, the height of the rolling
climbing step increases and the driving torque of the wheels also
increases. For obstacle-crossing mode using support legs, support force of
the ground on the leg decreases with the increase of climbing height, while
support force of the step on the main body increases with the increase of
climbing height. The rolling angle of the main body has a greater impact on
the support force and driving torque, while the contact angle between the
legs and the ground has a small impact.</p></list-item><list-item>
      <p id="d1e4484">The stability cone method is used to comprehensively evaluate the static and dynamic stability of the wheel–leg deformation mechanism. It is shown that the closer the support leg is to the step, the smaller the stability angle of the mechanism along the side line <inline-formula><mml:math id="M141" display="inline"><mml:mrow><mml:msub><mml:mi>a</mml:mi><mml:mn mathvariant="normal">3</mml:mn></mml:msub></mml:mrow></mml:math></inline-formula> without
external force interference so that the whole mechanism crosses the step.
The analysis on the anti-interference ability of the mechanism shows that
the existence of interference force has little influence on the stability of the system. The mechanism has good anti-interference ability.</p></list-item></list></p>
</sec>

      
      </body>
    <back><notes notes-type="dataavailability"><title>Data availability</title>

      <p id="d1e4503">The data that support the findings of this study are available from the corresponding author upon reasonable request.</p>
  </notes><notes notes-type="authorcontribution"><title>Author contributions</title>

      <p id="d1e4509">MZ conceptualized the study,
wrote the original draft of the paper, and reviewed and edited the paper. YS was responsible for data curation and validation.</p>
  </notes><notes notes-type="competinginterests"><title>Competing interests</title>

      <p id="d1e4515">The contact author has declared that neither of the authors has any competing interests.</p>
  </notes><notes notes-type="disclaimer"><title>Disclaimer</title>

      <p id="d1e4521">Publisher's note: Copernicus Publications remains neutral with regard to jurisdictional claims in published maps and institutional affiliations.</p>
  </notes><notes notes-type="financialsupport"><title>Financial support</title>

      <p id="d1e4527">This research has been supported by the Open Project of Anhui Province Key Laboratory of Special and Heavy Load Robot (grant no. TZJQR004-2022).</p>
  </notes><notes notes-type="reviewstatement"><title>Review statement</title>

      <p id="d1e4533">This paper was edited by Daniel Condurache and reviewed by two anonymous referees.</p>
  </notes><ref-list>
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